problem18_08

University Physics with Modern Physics with Mastering Physics (11th Edition)

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18.8: a) ( 29 ( 29 ( 29 ( 29 ( 29 kg. 373 . 0 K 15 . 310 K mol J 3145 . 8 m 0750 . 0 Pa 10 013 . 4 mol kg 10 0 . 32 3 5 3 tot = × × = = - RT MpV m b) Using the final pressure of Pa 10 813 . 2 5 × and temperature of kg, 0.275 K, 15 . 295
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Unformatted text preview: = ′ m so the mass lost is kg 098 . where extra figures were kept in the intermediate calculation of tot m ....
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