problem18_18

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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18.18: From example 18.4, the pressure at elevation y above sea level is . RT / 0 Mgy e p p - = The average molar mass of air is kg/mol, 10 8 . 28 3 - × = M so at an altitude of 100 m, , 01243 . 0 K) K)(273.15 mol J 3145 . 8 ( m) 100 )( s m 80 . 9 )( mol kg 10 8 . 28 ( 2 3 1 = × = - RT Mgy and the percent decrease in pressure is %. 24 . 1 0124 . 0 1 1 01243 . 0 0 = = - = - - e p p At an altitude of , 1243 . 0 m, 1000 2

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Unformatted text preview: Mgy and the percent decrease in pressure is %. 7 . 11 117 . 1 1243 . = =--e These answers differ by a factor of , 44 . 9 1.24% 11.7% = which is less than 10 because the variation of pressure with altitude is exponential rather than linear....
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• Mole, Mass, Above mean sea level, average molar mass

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