problem18_42

University Physics with Modern Physics with Mastering Physics (11th Edition)

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18.42: a) ( 29 ( 29 ( 29 ( 29 kg/mol 018 . 0 C J/kg 833 so , mass molar ° = C C v C mol J 0 . 15 ° = ( 29 ( 29 ( 29 × ° ° - ° = ° ° - C J/kg 2060 C, 60 at C J/kg 5 . 29 kg/mol 018 . 0 C J/kg 1640 C, 180 at ( 29 C. 0 . 5 at C J/mol 1 . 37 kg/mol 018 . 0 ° - ° = b) Vibrational degrees of freedom become
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Unformatted text preview: more important. c) O H because 3 exceeds 2 R C V also has rotational degrees of freedom....
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This document was uploaded on 02/05/2008.

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