problem18_53

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 18.53: a) ∆V = βVo ∆T = (3.6 × 10−5 °C) (11 L)(21°C) = 0.0083 L ∆V = − kVo ∆p = (6.25 × 10−12 Pa)(11 L) (2.1 × 107 Pa) = −0.0014 L So the total change in volume is ∆V = 0.0083 L − 0.0014 L = 0.0069 L. b) Yes; ∆V is much less than the original volume of 11.0 L. ...
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