problem18_68

University Physics with Modern Physics with Mastering Physics (11th Edition)

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18.68: J. 10 82 . 1 ) m 400 )( s m 80 . 9 ( mol molecules 10 023 . 6 mol kg 10 0 . 28 a) 22 2 23 3 - - × = × × = = = gh N M mgh U A b) Setting K. 80 . 8 K J 10 38 . 1 J 10 82 . 1 3 2 , 2 3 23 22 = × × = = - - T kT U c) It is possible, but not at
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Unformatted text preview: all likely for a molecule to rise to that altitude. This altitude is much larger than the mean free path....
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  • Mole, Molecule, 3 kg, 9.80 m, 10 J, 8.80 K

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