{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

finalKeyW06 - ENGR 213 Winter 2006 Final Exam Name K5 2...

Info icon This preview shows pages 1–8. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 8
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ENGR 213 Winter 2006 Final Exam Name: K5 2 Instructions: 1. Do not open the exam until you are told to do so 2. Fill in your name above 3. There are 4 equally weighted problems on this exam 4. This is a partial credit exam. All work must be shown in the space provided and must be legible for credit to be awarded. 5. The exam is 1 hour and 50 minutes long, so budget your time accordingly 6. You are permitted three 8.5 x 11 equation/note sheets 7. No worked problems are permitted on equation/note sheet 8. Write your name on your equation/note sheets and hand them in with your exam Do not write in this space 1) Shear and moment diagrams. a) For the given free-body diagram i) Draw shear diagram. (6 pts) ii) Label the diagram with values at cross-sections A through G. (12 pts) 25+51(x-4)2 ib/in 100 lb ‘ 100lb/in )00 j ES" CW, I W It” 7 v X Uli’: :20 - 47 IOO ~ £IOOJX+V" PW W a - Ea - r -- gkj) v i; -3: V, WZF =0 ‘ 7— . too “(0100 Jx g, 7. +[as+ 51(x-4)Jx / G 4+V=OJ DmazAM'. A—7E3 ) CaNSTAA/r Pas/T'n/E 5L 0P5 ® fiat) H0£i30NTA¢ (1471)) mm. N54. SLOPE @ 0915, thaw/imp 4‘1 Ei-ayF/ 1+d2120N779~L F767, mama/Um; @ b) For the given free-body diagram and shear diagram i) Draw the moment diagram (2 pts) ii) Label the diagram with values at cross-sections AB, and C. (5 pts) 1000 in-Ib. 2) A moment of 2500 in-lb is applied to the triangular cross-section beam as shown. The centroidal moment of inertia is 0.04688 in‘, Young’s modulus is 30 000 000 psi. a) What is maximum tensile stress in the x-direction? (5 pts) b) What is maximum compressive stress in the x-direction? (5 pts) c) What is the name given to the location of zero bending stress? (5 pts) d) If the answer to (a) was 50 000 psi, what is the minimum magnitude of axial load (a force along the x-axis) which would result in only zero or compressive stress acting on the cross-section? (5 pts) ' e) If the 2500 in—lb moment was n_ot applied, oould an axial load of 2500 lb be applied without buckling occurring? The length of the beam is 120 in. Show calculations to support your answer. (5 pts) M = 2500 in-Ib M = 2500 in-lb I A'L AX +9 55“ d) 0;)(134 c :48 -' mirth: ozx’m‘ + flail GET}. g 50 000 0 =Wm +— 500004’9/ n. >. max. *4 Pt” ‘ n‘iTfi'EI _ ~— 4/ 2 n 9) PM L1. '5» n=\) Yner \ n-pp\xc.A—H€. TT?’ L30 X/0‘>(0.0 4-é 88) +92 “94" /:Lo1 ER = 9M )2; F7: CR ER < 2500M +\ A/U/ BUdKL/A/4 WILL Uch/Z 3) A transverse shear force of 2500 lb. is applied to the triangular cross-section shown below. The centroidal moment of inertia is 0.04688 in“. The equation to calculate the stress caused by a transverse shear force is Assuming it is desired to calculate this stress at y = -0.5, answer the following: a) What is the correct value of V? (3 pts) b) What is the correct value of Q? (10 pts) c) What is the correct value of l? (3 pts) d) What is the correct value of b? (4 pts) 6) Where on the cross-section (y-coordinate) will the minimum shear stress occur? (5 PtS) _\ \4/2 X Q=jA via ‘49” *5 "I a; O ,m Q-—(m(t mimics} €1- ‘ ' ML,“ 5 = 0.0277813!“ M 4) A cantilever beam and its corresponding free-body diagram are shown below. The beam has an elastic modulus of 30 000 000 psi and a centroidal moment of inertia about the z-axis of 0.005 in“. The internal moment, M, is constant and equals 144 in- lb. a) What are the two boundary conditions needed to solve for the deflection? (4 pts) b) What is the slope of the beam at x = 6 in? (8 pts) 0) If the slope of the beam is given by the equation slope = 0.01 x what would the deflection be at x = 6 in? (8 pts) ‘ d) It’s been a fun term, have a good break! (5 pts) @ 144 in-lb y t 144 in-lb 144 in-lb () View 4" CV) v-’(o) =0 907530 M ['9 GEL/:_ M = M:‘0,0009é as? _ - a ’ (soxlo‘XmaE) W6“) if- _ 096 1“ (if 6"“ Mfldx' 0'00 'X C' J 0’“ \ {/0pé @ X26 )5 ¥\OP’[email protected] "0.00576, ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern