ExamFinalKey - ENGR 213 Spring 2007 Final Exam Solution Key...

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Unformatted text preview: ENGR 213 Spring 2007 Final Exam Solution Key 1 a Zero (10 pts.) b bo ho bI hI c = 0.080 H2 pts.L = 0.120 H2 pts.L = 0.064 H2 pts.L = 0.104 H2 pts.L 1 1 I= bo h3 bI h3 H10 pts.L o I 12 12 I = 5.52 x10-6 - m4 H1 pt. value, 1 pt. unitsL s = 150 x 106 H3 pts.L y = 0.06 H3 pts.L I = 4.0 x 10-6 H3 pts.L My s= H19 pts.L I M = 10 000 N - m H1 pt. value, 1 pt. unitsL M = 5000 H3 pts.L E = 70 x 109 H3 pts.L I = 4 x 10-6 H3 pts.L 1 M =H19 pts.L r EI d r = 56 - m H1 pt. value, 1 pt. unitsL 2 a V = 1200 - N (4 pts. value, 1 pt. units) b 2 examFinalKey.nb c = 0.120 H2 pts.L = 0.120 H2 pts.L = 0.080 H2 pts.L = 0.080 H2 pts.L 1 1 I1 = bo h3 bI h3 H5 pts.L o I 12 12 I = 1.39 x10-5 - m4 H1 pt. value, 1 pt. unitsL bo ho bI hI A = H0.120L H0.020L = 0.0024 H5 pts.L y = 0.040 + 0.010 = 0.050 H5 pts.L Q = A y H18 pts.L Q = 0.00012 - m3 H1 pt. value, 1 pt. unitsL b = 0.040 - m (19 pts. value, 1 pt. units) (for b = 0.020-m, give 10 pts. value and 1 pt. units) b d e t = 250 000 H2 pts.L A = H0.030L H0.020L H6 pts.L F t= H10 pts.L A F = 150 - N H1 pt. value, 1 pt. unitsL 3 a sz = 0 H10 pts.L sy = l sx Hgiven in problem statementL ez = 1 E sz n E ez = n E sx H1 + lL H10 pts.L Isx + sy M H20 pts.L examFinalKey.nb 3 b sz = 0 Hpoints given in part aL sy = l sx Hgiven in problem statementL Isy + sz M H20 pts.L E E 1-ln ex = sx H10 pts.L E E E = H5 pts.L 1-ln ex = 1 sx n E = E H15 pts.L c 4 a 1, 2, 3 (10 pts.) b 100 MPa (10 pts.) c Zero (10 pts.) d Principal strains (10 pts.) e G= 2 H1 + nL E H10 pts.L f dM dx g = V H10 pts.L 4 examFinalKey.nb g d2 v dx 2 =- M EI h P= H10 pts.L i 4 E IPi^2 H10 pts.L L2 The inner surface of the hollow shaft (10 pts.) ...
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This test prep was uploaded on 04/08/2008 for the course ENGR 213 taught by Professor Keil during the Spring '06 term at Oregon State.

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ExamFinalKey - ENGR 213 Spring 2007 Final Exam Solution Key...

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