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# Copy of chapter 1 - Chapter 1 Introduction Answers to Even...

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Chapter 1 Introduction Answers to Even Numbered Conceptual Questions 2. Atomic clocks are based on the electromagnetic waves that atoms emit. Also, pulsars are highly regular astronomical clocks. 4. (a) ~ -1 0.5 lb 0.25 kg or ~10 kg (b) 0 ~4 lb 2 kg or ~10 kg (c) ~ 3 4000 lb 2000 kg or ~10 kg 6. Let us assume the atoms are solid spheres of diameter 10 . Then, the volume of each atom is of the order of 10 . (More precisely, volume = 10 m -30 3 m π 3 41 = 36 r 3 d .) Therefore, since 1 , the number of atoms in the solid is on the order of = 3- 6 cm 10 m 3 6 24 30 10 = 10 10 atoms. A more precise calculation would require knowledge of the density of the solid and the mass of each atom. However, our estimate agrees with the more precise calculation to within a factor of 10. 8. Realistically, the only lengths you might be able to verify are the length of a football field and the length of a housefly. The only time intervals subject to verification would be the length of a day and the time between normal heartbeats. 10. On the average, a typical person drives about 10 000 miles per year or about 30 miles per day. (A reasonable estimate would be in the range of 5 to 50 miles per day.) 12. In general, the manufacturers are using significant figures correctly. The length and width of the aluminum foil both include three significant figures and the cited value of their product (the area) correctly includes three significant figures in both the metric and English versions. The manufacturer of the tape also gives three significant figures in the dimensions of the tape (metric version) and retains three significant figures in their product (area). However, the width of the tape is given in English units as 12 , which gives no indication of the accuracy of the measurement. To be consistent with the three significant figure accuracy cited in the metric width dimension, the width should be given as . 0.500 1

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2 CHA P T E R 1 Answers to Even Numbered Problems 2. (a) 2 LT (b) L 4. All three equations are dimensionally incorrect. 6. (a) (b) -2 MLT 2 kg m s 8. ± 22 209 cm 4 cm 10. (a) × 8 3.00 10 m s (b) × 8 2.997 9 10 (c) 8 2.997 924 10 m s × 12. (a) (b) ± 2 346 m 13 m 2 ± 66.0 m 1.3 m 14. (a) (b) × 9 2.96 10 × 2 6.876 10 16. (a) , , × 2 5.60 10 km × 5 5.60 10 m × 7 5.60 10 cm (b) , , 0.4912 km 491.2 m × 4 4.912 (c) , 6.1 , 6.192 km × 3 92 × 5 6.192 (d) , , 2.499 km × 3 2.499 × 5 2.499 18. 9.2 nm s 20. × 9 31 0y r 22. , × 2 3 2.9 × 8 3 10 cm 24. × 6 3 2.57 26. (a) = 1 mi h 1.609 km h (b) 88 km h (c) 16 km h 28. It would require about 47.6 yr to count the money. We advise against it. 30. of beef, ~ head of cattle (assumes 0.25 lb per burger and a net of 300 lb of meat per head of cattle) 10 ~10 lb 7 10 32. (assumes 7 ~10 blades 2 1 16 in per blade) 34. 10 ~10 cans yr , 5 ~10 ton yr (Assumes an average of 1 can per person each week, a population of 250 million, and 0.5 oz of aluminum per can) 36. 2.2 m
Introduction 3 38. 8.1 cm 40. 2.33 m 42. (a) 1.50 m (b) 2.60 m 44. 8.60 m 46. 70.0 m 48. (a) 3 0.677 g cm (b) × 17 2 4.63 10 ft 50. (a) (b) 2 ~10 kg 3 52. (a) (b) 2 ~10 yr 4 ~10 times 54. (a) 4 (b) 8

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4 CHA P T E R 1 Problem Solutions 1.1 (a) The units of volume, area and height are: , [] , and = 3 [] L V = 2 L A = We then observe that L h = 3 LL 2 L or = Thus, the equation VA h = V is dimensionally correct. A h (b) ( ) ππ == = 22 cylinder h R h VR , where A
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## This note was uploaded on 04/08/2008 for the course PHY 101 taught by Professor Pralle during the Spring '08 term at SUNY Buffalo.

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Copy of chapter 1 - Chapter 1 Introduction Answers to Even...

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