problem18_88

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
18.88: a) Following Example 18.4, , RT pM dy dP - = which in this case becomes , 0 αy T dy R Mg p dp - - = which integrates to . 1 or , 1 ln ln 0 0 0 0 α - = - = R Mg T αy p p T αy Mg p p b) Using the first equation above, for sufficiently small , ) 1 ln( , 0 0 T αy T αy α - - and this gives the expression derived in Example 18.4. c) , 8154 . 0 K) 288 ( m) m)(8863 C 10 6 . 0 ( 1 2 = ° × - - 6576 . 5 m) C 10 K)(0.6 mol J 3145 . 8 ( ) s m 80 . 9 )( 10 8 . 28 ( 2 2 3 = ° × × = - -
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online