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Unformatted text preview: (has one claim)= 70/250 = 0.28 b. P(in the highrisk category)= 25/250 = 0.10 c. P(OH) is the probability that a randomly selected driver has one claim in one year, given that he/she is in highrisk category. d. P(OH)= 21/25 = 0.84 e. NO, 0.84=P(OH) P(O)=0.28, so they are NOT independent. 3. a. We have X = # students in the sample of size n = 5 that live off campus. Then X is binomial with n = 5 and p = 0.70. To find the probability of at least 4, we use the binomial probability function. 5 5 P( X 4) = P( X = 4) + P( X = 5) = (.70) 4 (.30)1 + (.70) 5 (.30) 0 = 5(.70) 4 (.30) + (.70) 5 = 0.3602 + 0.1681 = 0.5283 4 5 b. We have X = #...
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This test prep was uploaded on 04/09/2008 for the course STAT 350 taught by Professor Gunderson during the Fall '08 term at University of Michigan.
 Fall '08
 Gunderson

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