problem21_p105

University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.105: a) For a rod in general of length + - = r L r L kQ E L 1 1 , and here . 2 a x r + = So, . 2 2 1 2 1 2 2 1 2 1 rod left + + - + = + + - + = a x L a x L kQ a x L a x L kQ E b) + + × = = = = 2 2 2 2 2 2 2 a L a a L a L kQ dx L EQ dq E F E dq dF dx a x L a x 2 2 1 2 1 + + - + ( 29 2 2 2 2 2 2 )] 2 2 [ln( )] 2 ( ln [ 2 1 2 a L a a L a a x L x a L kQ F + + + + - + = . ) 2 ( ) ( n 1 2 4 2 2 2 2 1n 2 2 2 2 2 + + = + + + + = L a a L a L kQ a L a L a a L a L kQ F c) For ) ) 2 1 ln( ) 2 (1 n 1 2 ( ) 2 1 ( ) 1 ( n 1 : 2 2 2 2 2 2 2 a L a L L kQ a L a a L a L kQ F L a + - + =
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Unformatted text preview: + + = . 2 2 2 2 2 2 2 2 2 2 2 2 a kQ F a L a L a L a L L kQ F ≈ ⇒ ⋅ ⋅ ⋅ +-- ⋅ ⋅ ⋅ +-≈ ⇒ Page 1 of 1...
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