problem22_05

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 22.5: a) = E A = 2 0r (2rl ) = l 0 = ( 6.0010-6 C/m) (0.400 m) 0 = 2.71 10 5 Nm 2 C. b)We would get the same flux as in (a) if the cylinder's radius was made larger--the field lines must still pass through the surface. c)If the length was increased to l = 0.800 m, the flux would increase by a factor of two: = 5.42 10 5 Nm 2 C. ...
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