Sheet_2_Quiz_1

# Sheet_2_Quiz_1 - for a finite sheet: = Q/A sheet Electric...

This preview shows page 1. Sign up to view the full content.

Coulomb's Law F = k(Q 1 Q 2 /r 2 ) F = G(m 1 m 2 )/r 2 k = 9.0 x 10 9 m 2 /C 2 e = 1.602 x 10 -19 C ε 0 = 8.85 x 10 -12 C 2 /Nm 2 Electric Field E = F/q (N/C) F = qE E = k(Q/r 2 ) E = E 1 + E 2 + . .... E = k(Q 1 /r 1 2 ) + k(Q 2 /r 2 2 ) + . .... a = qE/m q of an electron = 1.602 x 10 -19 C for an infinite plane : E = σ/2ε 0 E = (2kqdR – kQd 2 ) / (R 2 (R+d) 2) and if R>>d: E = 2kqd/R 3 Electric Dipoles p = dipole moment = Ql (Cm) Г = pEsinθ (N-m) W = pE (cosθ 2 - cosθ 1 ) U = -W = -pEcosθ along dipole axis: E = (2kp/R 3 )cosθ along perp. bisector of d: E = kp/R 3 (where R>>d) Electric Flux Φ E = EAcosθ (uniform E) Φ E = EdAcosθ (E is not uniform) Φ NET = Q/ε 0 Gauss's Law E = Q/(4πε 0 r 2 ) = Q/ε 0 for an infinite sheet: 2EA = σ/2ε
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: for a finite sheet: = Q/A sheet Electric Potential W = qEd U b U a = -W = -qEd Electric Potential V a = U a /q V ba = V b V a = -W ba /q W = K + U U = qV ba K = -U V ba = -Ed (E = V/m) V = kQ/r Electric Dipole Potential V = kpcos/r 2 Electron Volt U = kQ 1 Q 2 /r 1 eV = 1.6 x 10-19 J Vectors F x = F cos F y = F sin Magnitude = (Dx 2 + Dy 2 ) Angle = tan =Dy / Dx Motion at Constant Acceleration v = v o +at x = x o + v o t + 1/2at 2 v 2 = v o 2 + 2a(x x o ) average velocity = (v + v o ) / 2...
View Full Document

## This note was uploaded on 04/09/2008 for the course PHYS 10b taught by Professor Martens during the Spring '08 term at Brandeis.

Ask a homework question - tutors are online