problem22_06

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: −9 2 22.6: a)  Φ S1 = q1 ε0 = (4.00 × 10 C) ε0 = 452 Nm C. −9 2  b)  Φ S2 = q2 ε0 = (−7.80 × 10 C) ε0 = −881 Nm C. −9 2  c)  Φ S3 = (q1 + q2 ) ε0 = ((4.00 − 7.80) × 10 C) ε0 = −429 Nm C. −9 2  d)  Φ S4 = (q1 + q2 ) ε 0 = ((4.00 + 2.40) × 10 C) ε0 = 723 Nm C. −9 2  e)  Φ S5 = (q1 + q2 + q3 ) ε0 = ((4.00 − 7.80 + 2.40) × 10 C) ε0 = −158 Nm C.  f) All that matters for Gauss’s law is the total amount of charge enclosed by the surface, not its distribution within the surface. ...
View Full Document

This document was uploaded on 02/06/2008.

Ask a homework question - tutors are online