Lecture04

Lecture04 - Titration of Weak Acid with Strong Base Example...

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Titration of Weak Acid with Strong Base Example 12-6: Titration of 50.0 mL of 0.100 M acetic acid (K a = 1.75 x 10 -5 ) with 0.100 M NaOH. Initial pH = 2.88 Analytical Reaction: HOAc + NaOH -----> NaOAc + H 2 O Initially 0.100 M x 50.0 mL = 5.00 mmol HOAc Requires 5.00 mmol NaOH 0.100 M = 50.0 mL to E.P. Equivalence Point pH = 8.73 After E.P. pH is determined by xs NaOH. Exactly same as strong acid titration.
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Titration of 50.0 mL of 0.100 M HOAc with 0.100 M NaOH. 0 20 40 60 80 100 0 2 4 6 8 10 12 14 Volume of NaOH pH HCl HOAc Changes with Weak Acid 1. Higher initial pH 2. E.P. pH is greater than 7.00 3. Smaller change in pH at E.P.
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Titration of Weak Base with Strong Acid: 0 20 40 60 80 0 2 4 6 8 10 12 14 pH 100 NaOH NH3 Volume of HCl NH 3 + HCl -----> NH 4 + + Cl - Equivalence Point pH = 5.3 In general, salt formed at E.P. is weak acid (conjugate acid) so pH at E.P. < 7. Weak Acid/Weak Base: No sharp pH change at equivalence point. pH 7.00
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Titration of a Difunctional Acid or Base At First E.P. amphiprotic ion is formed:
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Lecture04 - Titration of Weak Acid with Strong Base Example...

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