Activity11WorkFeb26

# Activity11WorkFeb26 - below the horizontal. There is a...

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Activity 11 Work February 26, 2008 Use g = 10 m/s 2 and ROUND answers. 1. a. Determine the work done by the cable with a 12-N tension while pulling the 2.0 kg crate 4.0 m up the 37° incline. (length of the ramp is 4.0 m). b. Determine the work done by gravity on the crate while the crate is going 4.0 m up the incline. c. Draw a motion diagram for the motion up the ramp. What is the change in Kinetic Energy? 2a. Determine the work done by the cable with the 12-N tension while lowering the 2.0 kg crate 4.0 m down the 37° incline. b. Determine the work done by gravity on the crate while the crate is going 4.0 m down the incline. c. Draw a motion diagram for the motion down the ramp. What is the change in Kinetic Energy?

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A 60kg skier who starts at rest and moves down a ski slope that is inclined at 41.4°
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Unformatted text preview: below the horizontal. There is a sticky 0.20 coefficient of friction between the slope and the skis. The finish-line flag is 200m from the starting position. Use a gravitational constant is 10 m/s 2 . a. Draw the gravitational force acting on the skier? Which component does work? What is the work done by gravity? Is it positive Work or negative Work? Why? b. Draw the frictional force on the skier? What is the work done by friction? Is it positive Work or negative Work? Why? c. What is the work done by the normal force? Why? d. What is the total work done? e. What is the initial kinetic energy? What is the final kinetic energy? f. Determine the skier's speed as she reaches the finish line. g. REDO problem using NEWTON'S SECOND LAW. (use separate page) 41.4 200 m...
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## This test prep was uploaded on 04/08/2008 for the course PHYS 20910 taught by Professor Magee-sauer during the Spring '08 term at Rowan.

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Activity11WorkFeb26 - below the horizontal. There is a...

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