problem22_18

University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.18: Draw a cylindrical Gaussian surface with the line of charge as its axis. The cylinder has radius 0.400 m and is 0.0200 m long. The electric field is then 840 N/C at every point on the cylindrical surface and directed perpendicular to the surface. Thus = = ) 2 )( ( ) )( ( cylinder πrL E A E d s E
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Unformatted text preview: /C m N 42.2 m) (0.0200 m) (0.400 ) (2 N/C) 840 ( 2 = = The field is parallel to the end caps of the cylinder, so for them = s E d . From Gausss law: C 10 74 . 3 ) C m N 2 . 42 ( ) m N C 10 854 . 8 ( 10 2 2 2 12-- = = = E q...
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This document was uploaded on 02/06/2008.

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problem22_18 - /C m N 42.2 m) (0.0200 m) (0.400 ) (2 N/C)...

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