Solution_SP5

Solution_SP5 - Natural 1 606 1 00165 15 15 1000 4 = = = = =...

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3/31/2008 ME 145 - Solution to Supplemental Problem 5 ( 29 ( 29 ( 29 ( 29 ( 29 kW . MW . . . p v m W MPa p MPa . p MPa . Pa x . . . gH p . v . MPa v MPa p m pump f pump pump drop R f B f f f 6 105 1056 0 064 0 00165 0 1000 0.064 0.036 - 0.1 Needed Pump 1 0 036 0 10 6 3 300 1 606 12 8 9 rise pressure buoyancy
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Unformatted text preview: Natural 1 606 1 00165 15 15 1000 4 = = = = = = = = =-=-= = = = = = =...
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This homework help was uploaded on 04/09/2008 for the course ME 145 taught by Professor Manno during the Spring '08 term at Tufts.

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