Problem 2-105 (page 83)
Illustration of probability concepts
with independent events
Problem 2-108 (page 84)
Illustration of probability concepts
with independent events

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2-105
a) n=10
883
.
0
365
356
365
363
365
364
365
365
=
⋅
⋅
⋅
⋅
•
•
117
.
0
883
.
0
1
=
−
b) K such that
0.5 probability
that at least two have the same
birthday k
23
≥
≅

P( all 10 have different last 3 digits)
956
.
0
100
991
1000
999
1000
1000
=
⋅
⋅
⋅
•
=
Thus, the probability that at least two have the
same last 3 digits is 1-.956=.044
The answer to part c is therefore:
.117+.044-(.117)(.044)=.156

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