Exam 1 answers - Equation and Constant Sheet NA = 6.0221367...

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Equation and Constant Sheet N A = 6.0221367 x 10 23 R = 8.314472 J/mol K = 0.08205745 L atm/mol K c = 2.99792458 x 10 8 m/sec R = 0.082057 L atm/mol K 1amu = 1.661 x 10 -24 g 1 0 n – 1.008665 amu, 1 1 p – 1.007276 amu, 0 -1 e - 0.0005485799 amu = 9.10939 x 10 - 31 kg K.E. = ½ mv 2 = p 2 /(2m) p = mv PV = nRT 1
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CHEMISTRY 1100 Fall 06 Exam 1 USE PEN ONLY _______________________(PRINT) ________ _________ LAST NAME, FIRST NAME SECTION TABLE _____________________ 1.____________(25pts) DISC/LAB SECTION INSTRUCTOR 2.____________(25pts) 3.____________(25pts) 4.____________(25pts) ______________(Bonus 5pts) _______________(Total) SHOW ALL WORK! All essay questions must be answered with complete sentences. All calculations must be clearly shown with units and their cancellations in at least one step of the problem. Only exams written in ink are eligible for a re-grade. Academic Integrity is expected of everyone and anyone caught cheating will receive an F in the course. 2
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1._____________ (25pts) ___________________________ P r i n t I n i t i a l s (5pts for each question, all or nothing) __C______ (i) The density of liquid carbon tetrachloride, CCl 4 , is 1.60 g/mL. How many moles are there in a liter of pure CCl 4 ? (A) 11.3 mole (B) 33. 7 mole (C) 10.4 mole (D) 23.7 mole (E) 9.50 mole ___D_____(ii) What is the average atomic mass of Cl? There are two main isotopes of Cl: 35 Cl atomic mass of 34.97 amu and an abundance of 75.53% 37 Cl atomic mass 36.97 amu and an abundance of 24.47%. (A) 36.48 amu (B) 35.97 amu (C) 34.97 amu (D) 35.46 amu ____E____(iii) An enclosed mixture has a mass of 12.69723± 0.00003 g. After a chemical change occurs, the mixture has a mass of 12.69724± 0.00003g. These results show that (A) the law of conservation of mass is not always true. (B)
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This note was uploaded on 04/08/2008 for the course CHEM Chem 1100 taught by Professor Korenowski during the Fall '06 term at Rensselaer Polytechnic Institute.

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Exam 1 answers - Equation and Constant Sheet NA = 6.0221367...

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