University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.32: a) . C m N 750 ) m 0 . 6 )( C N 125 ( 2 2 = = = Φ EA b) Since the field is parallel to the surface, . 0 = Φ c) Choose the Gaussian surface to equal the volume’s surface. Then: 750 – EA = , C N 577 ) 750 C 10 40 . 2 ( 0 8 m 0 . 6 1 0 2 = + × = - ε E ε q in the positive x -direction. Since 0 < q we must have some net flux flowing
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Unformatted text preview: in so A E EA-→ on second face. d) < q but we have E pointing away from face I . This is due to an external field that does not affect the flux but affects the value of E ....
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  • gaussian surface, net flux, positive x -direction, face I.

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