ASA17 - = [HFor]/[For ] = 2.2 volume For = 20/2,2 = 9.0 mL...

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ASA for Expt. 17 1. pH = 3 2. a. [H + ] = 6.3 x 10 -6 b. [CN ] = 6.3 x 10 -6 [HCN] = 0.10 — 6.3 x 10 -6 = 0.10 (to 2 sig figs) c. K a = [H + ][CN ]/[HCN] = (6.3 x 10 -6 )( 6.3 x 10 -6 )/0.10 = 4.0 x 10 -10 3. a. [H + ] = 4.0 x 10 -4 [H + ] = K a ([HFor]/[For ]) [HFor]/[For ] = 4.0 x 10 -4 /1.8 x 10 -4 = 2.2 volume HFor/vol For
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Unformatted text preview: = [HFor]/[For ] = 2.2 volume For = 20/2,2 = 9.0 mL 4. OH (aq) + HFor (aq) For (aq) + H 2 O The added hydroxide ions react with HFor and are used up. No free hydroxide ions are present so that the pH does not change appreciably....
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This lab report was uploaded on 04/08/2008 for the course CHEM 128 taught by Professor All during the Spring '08 term at UConn.

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