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Unformatted text preview: 2+ is present and Bi 3+ is absent. Since the precipitate dissolves to some extent in alkaline solution, Sn 4+ and/or Sb 3+ must also be in the unknown. The orange precipitate formed on acidification of the alkaline solution must contain Sb 2 S 3 , which is orange, and may contain SnS 2 , which is tan. Thus: Cu 2+ and Sb 3+ are present, and Bi 3+ is absent and Sn 4+ is in doubt....
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- Spring '08