ASA20 - 2+ is present and Bi 3+ is absent. Since the...

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ASA for Expt. 20 1. 2. A. 2 H 2 S(aq) + Sn 4+ (aq) 4 H + (aq) + SnS 2 (s) B. 2 Sb 3+ (aq) + 3 H 2 S(aq) Sb 2 S 3 (s) + 6 H + (aq) C. Bi 3+ (aq) + H 2 O + Cl (aq) BiOCl (s) + 2 H + (aq) D. Bi 2 S 3 (s) + 12 H + (aq) + 6 NO 3 (aq) 2 Bi 3+ (aq) + 3 S (s) + 6 NO 2 (aq) + 6 H 2 O 3. — Since the precipitate obtained is black, Bi 3+ and/or Cu 2+ are present — Since that black precipitate when dissolved and in solution with 6 M HNO 3 produces a blue solution when treated with NH 3 , Cu
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Unformatted text preview: 2+ is present and Bi 3+ is absent. Since the precipitate dissolves to some extent in alkaline solution, Sn 4+ and/or Sb 3+ must also be in the unknown. The orange precipitate formed on acidification of the alkaline solution must contain Sb 2 S 3 , which is orange, and may contain SnS 2 , which is tan. Thus: Cu 2+ and Sb 3+ are present, and Bi 3+ is absent and Sn 4+ is in doubt....
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