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Unformatted text preview: moles H + = (1.0 mol/L) x 0.010 L = 0.010 mol [H + ] = 0.010 mol /0.050 L = 0.20 M b. rate = [I 2 ] /t = (0.0010 mol/L)/120 s = 8.3 x 106 mol/Ls 8.3 x 106 = k(1.60) m (0.20) p (0.0010) n c. 8.3 x 106 /4.0 x 106 = k(1.60/0.80) m (0.20/0.20) p (0.0010/0.0010) n 2.1 = 2 m ; m ≈ 1 4. This mixture contains twice as much I 2 as the one in #3. If the reaction is 0order in I 2 , the rate of the reaction does not depend on [I 2 ]. If there is twice as much I 2 , it will take twice as long for the color to disappear at the same rate . So, it will take 240 seconds....
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This lab report was uploaded on 04/08/2008 for the course CHEM 128 taught by Professor All during the Spring '08 term at UConn.
 Spring '08
 all
 Mole

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