PS5 solutions

PS5 solutions - PROBLEMS 3. (b) (c) 7. (b) (c) 9. H+ ( aq )...

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PROBLEMS 3. (b) + 2 H( ) OH( ) HO aq aq +→ (c) + 24 34 H( ) HPO ( ) HPO( ) aq aq aq + U 7. (b) 14 w 11 . 0 1 0 KK == × (c) 32 HPO 1 1 (7.1 10 ) 1.4 10 × = × 9. +4 a [HLac] [HLac] [H ] HLac 1.4 10 [Lac ] [Lac ] K −− = × × (a) 4 0.250 [H ] 1.4 10 1.4 10 0.250 × ; pH = 3.85 (c) 4 0.250 [H ] 1.4 10 4.4 10 0.0800 × ; pH=3.36 15. (a) HF F (b) 23 3 HCO (c) 44 HPO PO 17. pH = 9.40; +1 0 [H ] 4.0 10 M (a) 3 10 11 2 3 [HCO ] 4.0 10 4.7 10 [CO ] ×= ×× ratio = 10 11 (4.0 10 ) (4.7 10 ) 8.5 = (b) 3 HCO 8.5 0.225 mol 1.9 mol n = (c) 2 3 CO 0.475 0.336 ( ) 8.5 n ; 2 3 CO 0.0188 n = mass Na CO = 0.0188 mol × 106 g/mol = 2.0 g (d) 0.200 mol/L 8.5 0.735 0.139 V × ; V = 4.3L 21. pH = 4.50; +5 [H ] 3.2 10 M HLac 54 3.2 10 1.4 10 250.0/112.1 n HLac 0.510 mol n = (mL) 1.20 g/mL 0.730 0.510 mol 90.1 g/mol V = V = 52 mL
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CHAPTER 14 25. (a) 24 2 4 HPO +8 a24 HPO 8 0.500 0.300 [H ] H PO 6.2 10 0.317 0.300 9.8 10 ; pH = 7. 01 n K n −− × = × × × (b) 0.150 mol 0.050 mol 0.200 mol n =+= 2 4 HPO 0.0951 mol 0.0500 mol
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PS5 solutions - PROBLEMS 3. (b) (c) 7. (b) (c) 9. H+ ( aq )...

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