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PS6 solutions - CHAPTER 14 PROBLEMS 37. pH = 7.40; (a) (b)...

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CHAPTER 14 PROBLEMS 37. pH = 7.40; +8 [H ] 4.0 10 M (a) + 23 87 a2 3 3 [H ] [H CO ] (4.0 10 ) (4.4 10 ) 0.091 HCO [HCO ] K −− == × × = (b) Take 3 [HCO ] = 1.000 M , [H CO ] = 0.091 M +7 7 3 [H CO ] 0.241 [H ] H CO 4.4 10 1.25 10 0.850 [HCO ] KM = × × = × pH = 6.90 (c) 8 0.091 0.85 [H ] 4.4 10 3.36 10 1.000 0.091 0.15 × × = × pH = 7.47 39. (a) MO (b) PP (c) any (d) MO 41. (a) a p K = 8.2; 9 a 6.3 10 K (b) 7.2 – 9.2 (c) purple 43. (a) + 2 H( ) OH( ) HO aq aq +→ (b) 2+ 3 Ba , NO ions (c) + OH H 2(0.05000L)(0.237 mol/L) 0.0237 mol nn = 0.0237 mol 0.0592 L=59.2 mL 0.4000 mol/L V (d) [OH ] = 0.474 M ; pOH = 0.324; pH = 13.68 (e) 0.0237 mol/2 [OH ] 0.149 (0.05000 0.0296) L M + ; pOH = 0.83; pH = 13.17 (f) 7.00
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CHAPTER 14 45. (a) 2 H B u t ()O H () B u t ()HO aq aq aq −− +→+ (b) + But , Na (c) HBut n = (0.05000)(0.350) mol = 0.0175 mol 0.0175 0.0778 L 77.8 mL 0.225 V == = (d) +2 5 a [H ] [HBut] 1.5 10 0.350 K × ; + [H ] =0.0023 M ; pH = 2.64 (e) +5 [H ] 1.5 10 M ; pH = 4.82 (f) At the equivalence point, we have a solution of NaBut But HBut nn = orig. = 0.0175 mol V = 50.00 mL + 77.8 mL = 127.8 mL 0.0175 mol [But ] 0.137 0.1278 L M 14 5 10 b (1.0 10 ) (1.5 10 ) 6.7 10 K −−− × = × 21 0 1 1 [OH ] 6.7 10 0.137 9.2 10 × -6 [OH ] 9.6 10 M ; pOH = 5.02; pH = 8.98 56. (a) EQ (b) GT (c) GT (d) MI (e) LT CHAPTER 15 3. (a) 242 2 2 [Cr(C O ) (H O) ] (b) + 34 [Cr(NH )SO ] (c) + 322 [Cr(en)(NH ) I ] 5. (a) 6 (b) 4 (c) 2 (d) 4 7. (a) +3 (b) +2 (c) +1 (d) +2 9. (a) 22 3 4 [Mo(CNS) (en) ] PO
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PS6 solutions - CHAPTER 14 PROBLEMS 37. pH = 7.40; (a) (b)...

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