problem22_42

University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.42: a) We need: . 28 3 3 28 ) ) 2 (( 3 4 3 3 3 3 - = - = - = - πR Q ρ ρR π Q R R ρ Q π b) , 0 , 2 and 0 , = = < E R r E R r since the net charges are zero. ). ( 3 4 ) ( 3 4 ) 4 ( , 2 3 3 2 0 2 0 3 3 0 0 2 R r r ε ρ r πε Q E R r ε ρ π ε Q πr E R r R - + = - + = = Φ < < Substituting ρ from (a) . 3 0 2 0 28 7 2 R πε Qr r Q πε E - = c) We see a discontinuity in going from the conducting sphere to the insulator
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