problem22_53

University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.53: a) At N. 94 , 2 2 15 2 19 0 2 Fe e 0 m) 10 1 . 7 ( 4 C) 10 6 . 1 )( 82 ( 4 1 4 4 1 e = = = = = - - × × πε R q q πε E q F R r So: . m/s 10 1.0 kg 10 11 . 9 N 94 2 32 31 × = × = = - m F a b) . m/s 10 1 . 4 4 , At 2 32 (a) × = = = a a R r c) At 8 1 8 1 ( ) 82 ( , 2 e Q R r = = because the charge enclosed goes like 3 r ) so with the radius decreasing by 2, the acceleration from the change in radius goes up by
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