University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.54: a) The electric field of the slab must be zero by symmetry. There is no preferred direction in the y - z plane, so the electric field can only point in the x -direction. But at the origin in the x -direction, neither the positive nor negative directions should be singled out as special, and so the field must be zero. b) Use a Gaussian surface that has one face of area A on in the
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Unformatted text preview: y-z plane at , = x and the other face at a general value . x Then: , : ε ρx E ε ρAx ε Q EA d x encl = ⇒ = = = Φ ≤ with direction given by . ˆ | | i x x Note that E is zero at . = x Now outside the slab, the enclosed charge is constant with : x , : encl ε ρd E ε ρAd ε Q EA d x = ⇒ = = = Φ ≥ again with direction given by . ˆ | | i x x...
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