Ch5ActivitySolution - Solution to last chapter 5 activity problem As we showed in step 3 for a given sample size n the null hypothesis is rejected if

Ch5ActivitySolution - Solution to last chapter 5 activity...

This preview shows page 1 out of 1 page.

Solution to last chapter 5 activity problem As we showed in step 3, for a given sample size n , the null hypothesis is rejected if M n - 280 14 . 2 / n ≤ - 1 . 645. We want the probability of this event (the “power”) to be .95: P M n - 280 14 . 2 / n ≤ - 1 . 645 = . 95 We also know from the CLT that M n - 273 . 4 14 . 2 / n is approximately standard normal. We need to re-write the probability above in terms of this random variable: P M n - 280 14 . 2 / n ≤ - 1 . 645 = . 95 P M n - 280 - 23 . 359 n = . 95 P M n - 23 . 359 n + 280 = . 95 P M n - 273 . 4 - 23
Image of page 1

You've reached the end of your free preview.

Want to read the whole page?

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes