problem22_66

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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22.66: a) Charge enclosed: . 233 480 480 233 120 47 32 3 , Therefore . 120 47 160 31 24 7 4 ) ) ( 1 ( 4 and . 32 3 16 4 1 6 2 3 4 where 3 3 3 2 / 3 3 2 2 0 3 4 3 2 / 0 0 πR Q α παR παR Q παR παR dr r R r πα Q παR R R πα dr R αr π Q Q Q Q R R R i i = = + = = - = - = = = = + = b) = = = = = Φ r R πε Qr R ε αr E R ε παr r d R r α ε π πr E R r 0 4 0 2 0 2 0 4 3 0 2 . 233 180 16 6 2 3 2 3 4 4 : 2 enclosed. is charge all since , 4 : . 1920 23 5 1 3 1 233 480 480 17 5 1 3 1 4 4 128 3 160 5 24 3 4 ) ) / ( 1 ( 4 4 : 2 2 0 5 3 2 0 5 3 0 3 0 3 3 2 5 3 3 0 0 2 / 2 2 0 0 2 r πε Q E R r R r R r r πε Q E R r R r ε παR ε παR R R r R r ε πα ε Q r d r R r ε πα ε Q πr E R r R i r R i = - - = - - + = + - - + = - + = = Φ c) The fraction of Q between : 2 R r R . 807 . 0 233 480 120 47 = = Q Q o d) ,
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