quiz sol 2

# quiz sol 2 - = 1 2 1 2 Pr Pr P P = 93 5 4 72 23 Pr 4 2 Pr 1...

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Washington State University ME 402: Thermal System Design Quiz 1 Solution 1. a) 1 = x b) = = 0 vdP W c) s kg m 100 = d) () () MW kg kj s kg h h m Q 6 . 158 2 . 2794 2 . 4380 100 1 2 = = = The problem statement should be changed to saturated steam instead of saturated water! 5 points 2. a) 0 = Q b) s kg m m out in 10 = = c) kg kj h h i 74 . 555 1 = = 86 . 11 Pr 1
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Unformatted text preview: = 1 2 1 2 Pr Pr P P = 93 . 5 4 72 . 23 Pr 4 2 Pr 1 2 = = × ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ = ===> from the table kg kj h 8 . 451 2 = ( ) kW h h m W 4 . 1039 2 1 = − = & c) = ∆ s s kg m MPa P 10 1 2 2 = = & s kg m MPa P 10 5 1 1 = = &...
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## This homework help was uploaded on 04/09/2008 for the course ME 402 taught by Professor Doe during the Fall '07 term at Washington State University .

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