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2005_Pulmonary - r Physifllflgj-Fmfllfllflflfll‘f...

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Unformatted text preview: ' r. Physifllflgj-Fmfllfllflflfll‘f Exam 3 Student Test Report flu PULMU'N 1 A Course #: BIGMSD‘? Phyéidldgy Ingmar Dr. Erma Gourd: Title: Physidldgy ' Ddsrripfidn: Physidldgy Dayfl‘imd: Tem'fi'ear: Third Student Name: *5“ Student ID: u 11mm: Pts. Raw 11m 1313!] Raspmm: idashh- mm mums: ch- rnurtipla marks Dflfifl'ipfiflfl: dahhabdt: student‘s imam rape-nae f:- hunus test item —--_------- —m-m------- Rgmaflcs: Hdtd: mm m rdfiddta 1 palm added fdlldwlng past last mluafidn df #1:)- —P A. alveolar ducts '4? . FE“ 0h [mtg r37. tilveolar sacs~ fffi'P. gang, Mfihflfl Tm 1’59 53" mime“ we” no case MWE . pleura none of the shore 2. At the beginning of expiration a transmural pressure gradient exists across the 1'qu wall because the pressure is less than the pressure. I E .intraplenralrintra-alueolar. 11? E. infra-alveolar, intraplenral as”. intraplenral, atmospheric. Mu J31 atmospheric, intrapleura] E. none of the shore pm} - A 3. Most carbon dioxide is carried in blood: ‘ lawn _.a- dissolved ME Plasma fléctnanate . botmdto hemoglobin .4. + , £5 bound to carhoxii'hemoglohin. (301.1; “10:?- ”11:05 .—- H Hm; “Bf 13'“de Plasma proteins. E. none of the above 4. Increases in levels of'which of the following would lead to a shift in the 1th DYE? oxyhemoglohin saturation curve to the right? ‘ , ® ah s . decreased 2,3 DPG )3: decreased CD: E. none of the above 5. Ifaperson suffered a stab injur},F and airentered the intrapleura] Space (pneurnothoraJ-r], the most likelyF response would he for the: [um] collapse! {1% W61“ cufithCET ,Aflnng to expand outward and the chest wall to spring inward my ,Bt'lnng to expand outward and the chest wall to spring outward C. lung to collapse inward and the chest wall to collapse inward ® lung to collapse inward and the chest wall to spring outward E. lung volume to remain the same and the chest wall to spring outward lea A 6. In the regulafien ef ventilaflen and perfiJsien tn the lungs: C, (-3 Q) an inereeae in CD; at ‘2’ eanaea brenehielar dilatien‘f Fan increase int]: at ‘2’ eanaea breachielar dilatiee ’12:" a decrease in [he]: ‘1’ eaneea brenehielar eenatrietien Hnene efthe abeve . T. The diflilaien ef a gie always driven by: Al ita eeneentratiea Wfifil PW EEHVL J. fiaetienal eentent r J, Parfial Pressure :Pwssbtfl QWW ' . its aelnbilitg,r E. nene ef the above 3. The reaaen that the earetld and aertie beam.r ehenrereceptera de net stimulate respiraflen when there is an inereaae in earben mennraide binding te hemeglebin is that: 4:} a. they eel}; reapendte bigharterialPfl; TCO j; ,3: the}r enljr reapend te increased arterial pH they anal}.F respond te decreased arterial PUD; M W [W (:01 leads ' f g . henreglebin deea net ereaa the bleed brain barrier ' h 1‘ CE K9 i E nene ef the above 01 V“ g ' r-l i —:—_-, <_ a E) a. Peri2 is greatestin: ”Imi- IA? atmospheric: air —-7- B. fissues 4C. Ej'SI-Bmlflflrtfiflll ms. Cl} “3 W15: ,prulmenaryvein fi’m‘“ quflw T j" I} E? rinse C 1s. Wt happens ifminute ventilatien is achieved by decreasing the tidal volume by ens-half and deubling the halving tidal 1trelunie and deubfing the fi‘BqllfiflG‘j' efhreething [rate]? .es “:2: we" , : (.srflfio = a “if mi“ W0" 2'5 1:65.51 W is f lifi T b '_ J A. thedeadspaeeairinemses 1:34;: 4,: '- :[-‘§‘.1}1|? ' Emedeadspaeeajrflaysmsssme 1.1 “T2 5 5:5 E. the anaeunt efahnespherie air tn the lungs increases I53” 25; ii) gill} .aEII fliesmmmtefatmespherieairtethelungs stays the same “Why-315:1?) 1155‘:- [335513 E. nene eftheaheve fit, liege-.5: 335‘" .I " D i: D —.___—_——~—H4474—z—%fl , 51:, ' Answer “A” if true; “B” if false / A 11. Surfaetant Redness sin-face tension, therefere'mimnfisflfi: @mie (Piggil‘i: lull?” Hm C:$tl‘f~liP,¢Qa E) IL The flutetienal residual eafliy is determined by the passive elastic ferees nfthe lungs and the theraeie wall at the end nfa relaxed expiratiett. F RC = ER“ 4 EV A. true ease {X 13. The walls ef the airwafi expand were during inspiratien than during eapiratinn B. false Us: the diagram helnw ts answer questions 14-16: lass E) 14. The lung is Inn-r6 nnnnpunn: at the beginning nfnnnnnsnn thnn dun'ng the middls nf r r 5.3 F— .. ‘3 Atmn an 3: It) A 15. Thslungisgjerémmpliant duriggthafu'st part ofimpiratianthanduringthclast partnfespirnflnn: fiqufiihj. 251} W L} 515' (“r 519' 5 3 mm 13-15 T’ " 25' 2'! * 2. Jaime: E) 16. Lung samplianse = C = flP fflV: at! nm '5'? @fialse 1A 1?. Quiet aspirations are passive due tn thus mil fifths lungs: @m filssfictw sf lungs E. false ' ...
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