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sample2_extra problem_soln

# sample2_extra problem_soln - × ω = ⇒ × ω = j k i r v...

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4. If we let “W” refer the cylindrical wheel, “C” refer to its center, and “I” where it touches the surface, and we let “R” refer to the rod, setting i to be the direction of the motion of the wheel, j , directed from “C” to “I”, and (finally) let “F” be the frame where the pin and surface are stationary ( ) R v R v C C C C IC C I C ω =
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Unformatted text preview: × ω + = ⇒ × ω + = j k i r v v v v v v ( ) ( ) ( ) j i k j i i r v v v − − × ω + + + = ω ⇒ × ω + + = R v R R R C C AC R F A R C F C 2 2 / 2 / / / / v i-direction: ( ) R R C C R v R ω + = ω 2 2 / 2 / ; j-direction: ( ) R R C R v ω − = 2 2 / 2 / Combining these two equation: R C ω = ω 4 ; answer: 4 rad/s k...
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