Problem solving Chemistry 4

# Problem solving Chemistry 4 - Problem solving Chemistry Cu2...

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Problem solving Chemistry 4/25/2014 Cu 2+ + 2e -  Cu(s) 2H 2 O  O 2 + 4H + + 4e - Reduced constant current for five hours 404mg Cu What is the current? Current= Charge/ time Charge= Time= 5 hours .404g x (1 mol Cu)/(63.6g) x (2 mol e - / 1 mol Cu) x (9.6485x 10 4 C/ 1 mol e - )= 1.226 x 10 3 C Current= (1.226 x 10 3 C) / (1.80 x 10 4 s) = 6.81 x 10 -2 A The current is 6.81 x 10

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Unformatted text preview: -2 A Ga (Z= 31) [Ar]4S 2 4s 2 3d 10 4p 1 1s 2s 2p 3s 3p 3d 4s 4p 4d 4f 5s 5p 5d 5f 5g 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 1 5s 1s 2 2s 2 2p 6 3s 2 2p 6 3d 10 4s 2 2p 1 Tellurium Z= 52 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 5p 4 [Kr] 5s 2 4d 10 5p 4 Fe 1s 2 2s 2p 3s 3p 3d 4s SCl 2 Cl- S- Cl...
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• Fall '14
• Chemistry, mol Cu, Current= Charge/ time

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