This preview shows page 1. Sign up to view the full content.
Unformatted text preview: We dissolved TUMS in 0.3M HCl and the resulting mixture was titrated with 0.3M NaOH. We determined the amount of unrelated HCl by analyzing the amount of NaOH used, and once we found the unreacted amount we subtracted it from the total to determine the amount of calcium carbonate. The percent content of the active ingredient was 81%. Once, again, this part relied on titration which is a tricky procedure and is reliant on personal perception, thus minor error may have occurred. Step 1: CaCO 3 (aq)+H + (aq)->Ca 2 + (aq)+HCO 3-(aq) K=[[Ca 2 + ][HCO 3-]]/[[CaCO 3 ][H + ]] Step 2: HCO 3-(aq)+OH-(aq)->CO 3 2-(aq)+H 2 O(l) K=[CO 3 2-]/[[HCO 3-][OH-]]...
View Full Document
- Fall '07