L22_phys131_7nov07

L22_phys131_7nov07 - 3 1 v v Cf Ci Cf Of Cf Ci Of Ci Oyf Cyi yf yi Cf Ci Cxf Cxi xf xi Cf Ci Of Cf = θ = = θ = = θ = θ = θ = = = θ = = = θ

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Summary for Lecture 22 on November 7, 2007 Impulse J and Momentum P i t t f i n 1 i i SYS P P dt F J v m P f i - = = = Conservation of momentum: If impulse J is zero, then i f P P = even if mechanical energy isn’t conserved!
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HARD PROBLEM : a cue ball hits an object ball. After the collision, the cue ball’s motion is at a 90° angle to the motion of the object ball. The ratio of speed of the cue ball after the collision and the object ball is . What is the ratio of the velocity between the initial and final speed of the cue ball? All balls have the same mass. 3 : 1 Cue ball +y +x
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Cue ball +y +x 2 cos 1 v v . 60 so 3 v v tan ) before from ( v cos v v sin v mv 0 0 mv P P v cos v 0 mv 0 mv P P ? v v is What
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Unformatted text preview: 3 1 v v Cf Ci Cf Of Cf Ci Of Ci Oyf Cyi yf yi Cf Ci Cxf Cxi xf xi Cf Ci Of Cf = θ = = θ = = θ = θ = θ + = + = = θ + = + = = θ Summary of analogy between translational and rotational kinematic equations: x a 2 v v t a 2 1 t v x x at v v 2 v v v x 2 i 2 f 2 x x f i AV =-+ + = + = + = Translational Rotational αθ = ϖ-ϖ α + ϖ + θ = θ α + ϖ = ϖ ϖ + ϖ = ϖ 2 t 2 1 t t 2 2 i 2 f 2 f i AV...
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This note was uploaded on 04/09/2008 for the course PHYS 131 taught by Professor Reay during the Fall '08 term at Ohio State.

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L22_phys131_7nov07 - 3 1 v v Cf Ci Cf Of Cf Ci Of Ci Oyf Cyi yf yi Cf Ci Cxf Cxi xf xi Cf Ci Of Cf = θ = = θ = = θ = θ = θ = = = θ = = = θ

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