L6_phys131_1oct07

# L6_phys131_1oct07 - Shoot the can problem y h h L tan v 0...

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ball launcher ball ground x y y h L θ Shoot the can problem ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 QED tan L h cos v L sin v t sin v h t g 2 1 h t g 2 1 t sin v . y y , hit they If t g 2 1 h y t g 2 1 t v y y L t cos v tan L h 0 0 0 2 2 0 C B 2 C 2 y 0 0 B 0 θ = θ θ = θ = - = - θ = - = - + = = θ θ =

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Another ball launch problem: Two angles for hitting target! θ L ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ! works also 71 . 84 ) 29 . 5 90 ( so , cos sin 29 . 5 s / m 40 s m 8 . 9 m 30 sin 2 1 v g L sin 2 1 g 2 sin v g cos sin 2 v g sin v 2 cos v L : equation " x " o int t this Put g sin v 2 t t g 2 1 t sin v 0 0 : y t g 2 1 t v y y : y t cos v t v L : x 0 0 0 0 2 2 1 2 0 1 2 0 2 0 0 0 0 2 0 2 y 0 0 0 x 0 = - θ
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## This note was uploaded on 04/09/2008 for the course PHYS 131 taught by Professor Reay during the Fall '08 term at Ohio State.

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L6_phys131_1oct07 - Shoot the can problem y h h L tan v 0...

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