L12_phys131_15oct07

L12_phys131_15oct07 - Summary for Lecture 12 on Calculating with frictional forces Ff Ff K S N moving N(static varies between 0 and 1 for a large

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Summary for Lecture 12 on October 15, 2007 Calculating with frictional forces: ) static ( N F ) moving ( N F S f K f μ = μ = μ varies between 0 and 1 for a large class of problems. Moving friction has the value given, but the static friction formula gives only the maximum possible value. The actual value can be anywhere from zero to the maximum, and its direction can vary according to circumstances.
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A block sliding at 15 m/s starts up a ramp inclined at 30 0 with respect to horizontal. The sliding coeficient of friction between the ramp and block is 0.4. How far up the ramp will the block go before it stops? Approximate the block as a point. Construct a freebody diagram & turn it into x and Y force equations. (It’s convenient to use a “tilted coordinate system) The equations can be solved to obtain the net deceleration. 1D kinematics then gives the stopping distance v = 15 m/s 0 30 = θ +y +x
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Solution for block sliding up plane ( 29 ( 29 ( 29 ( 29 ( 29 [ ] ( 29 ( 29 ( 29 m 6 . 13
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This note was uploaded on 04/09/2008 for the course PHYS 131 taught by Professor Reay during the Fall '08 term at Ohio State.

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L12_phys131_15oct07 - Summary for Lecture 12 on Calculating with frictional forces Ff Ff K S N moving N(static varies between 0 and 1 for a large

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