# chapter17 - 1 Chapter 17 171. (a) X-bar Chart: UCL = 34 ....

This preview shows pages 1–4. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 Chapter 17 171. (a) X-bar Chart: UCL = 34 . 32 + 0 . 577(5 . 65) = 37 . 58 LCL = 34 . 32- . 577(5 . 65) = 31 . 06 R chart: UCL = 2 . 115(5 . 65) = 12 LCL = 0 There is one observation beyond the upper control limit. Removal of this point results in the following control charts: 2 The process now appears to be in control. (b) = R d 2 = 5 . 74 2 . 326 = 2 . 468 ,PCR = USL- LSL 6 = 20 6(2 . 468) = 1 . 35 PCR K = min 45- 34 . 09 3(2 . 468) , 34 . 09- 25 3(2 . 468) = min[1 . 474 , 1 . 2277] = 1 . 2277 (c) 0 . 205% 3 172. P ( X < + 3 / n | X = + 1 . 5 ) = P ( Z < + 3 / n- ( + 1 . 5 ) / n = P ( Z < 3- 1 . 5 n ) = probability of failing to detect shift on 1st sample following the shift. [ P ( Z < 3- 1 . 5 n )] 3 = prob of failing to detect shift for 3 consecutive samples following the shift. For n = 4, [ P ( Z < 0)] 3 = (0 . 5) 3 = 0 . 125 For n = 4 with 2-sigma limits, [ P ( Z < 2- 3)] 3 = [ P ( Z <- 1)] 3 = (0 . 1587) 3 = 0 . 003997 173. (a) ARL = 1 / (b) ARL = 1 / (1- ) (c) If k changes from 3 to 2, the in-control ARL will get much shorter (from about 370 to 20). This is not desirable....
View Full Document

## This homework help was uploaded on 04/09/2008 for the course ENGR, STAT 320, 262, taught by Professor Harris during the Spring '08 term at Purdue University-West Lafayette.

### Page1 / 13

chapter17 - 1 Chapter 17 171. (a) X-bar Chart: UCL = 34 ....

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online