chapter16 - 1 Chapter 16 161. H0 : = 7.0 ~ H1 : = 7.0 ~ =...

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1 Chapter 16 16–1. H 0 : ˜ μ = 7 . 0 n = 10 H 1 : ˜ μ = 7 . 0 α = 0 . 05 CR : R R * α (Table X) R + = 8 , R - = 2 R = 2 Since R > R * α , do not reject H 0 16–2. H 0 : ˜ μ = 8 . 5 H 1 : ˜ μ 6 = 8 . 5 α = 0 . 05 R + = 8, R - = 11, R = min(8 , 11) = 8, R * 0 . 05 = 5 Since R > R * 0 . 05 , do not reject H 0 16–3. (a) H 0 : ˜ μ = 3 . 5 Critical Region: R - < R * d H 1 : ˜ μ > 3 . 5 (b) n = 10 α = 0 . 05 R * 0 . 05 = 1 R = 3 Since R - > R * 0 . 05 , do not reject H 0 (c) Probability of not rejecting H 0 μ = 3 . 5) when ˜ μ = 4 . 5 p = P ( X > 1) = Z 1 1 β e - (1 ) x dx = e - 1 16–4. n = 10 σ = 1 H 0 : μ = 0 H 1 : μ > 0 (a) α = 0 . 025 (b) p = P ( X > 0) = P ( Z > - 1) = 1 - Φ( - 1) = 0 . 8413 R * 0 . 05 = 1 β = 1 - 1 X x =0 ± 10 x (0 . 1587) x (0 . 8413) 10 - x = 0 . 487
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2 16–5. H 0 : ˜ μ d = 0 H 1 : ˜ μ d 6 = 0 α = 0 . 05 CR : R < R * 0 . 05 = 1 R - = 2 , R + = 6 R = 2 Since R is not less than R * , do not reject H 0 16–8. H 0 : μ = 7 R + = 50 . 5 H 1 : μ 6 = 7 R - = 4
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This homework help was uploaded on 04/09/2008 for the course ENGR, STAT 320, 262, taught by Professor Harris during the Spring '08 term at Purdue.

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chapter16 - 1 Chapter 16 161. H0 : = 7.0 ~ H1 : = 7.0 ~ =...

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