Version 725 – Exam 1 – Mccord – (50970)
1
This
printout
should
have
31
questions.
Multiplechoice questions may continue on
the next column or page – find all choices
before answering.
001
10.0 points
The higher the energy of electromagnetic ra
diation, the
1.
longer its wavelength.
2.
greater its mass.
3.
higher the velocity of light.
4.
lower its frequency.
5.
shorter its wavelength.
correct
Explanation:
For electromagnetic radiation, the energy
of radiation is related to its frequency by the
equation
E
=
h ν ,
where
h
is Planck’s constant,
ν
=
c
λ
, and
c
is the speed of light in a vacuum (also a
constant).
Thus, the equation that relates energy to
wavelength for electromagnetic radiation is
E
=
h c
λ
As energy increases,
ν
(frequency) must also
increase, and
λ
(wavelength) must decrease.
002
10.0 points
Which of the following best describes the
range of atomic radii?
2.
1 to 15
˚
A
3.
5 to 10
˚
A
4.
10 to 30
˚
A
5.
0.4 to 3
˚
A
correct
6.
1 to 100
˚
A
Explanation:
Atomic radii vary from 30 pm (He) to 300
pm (Fr).
1
˚
A= 10

10
m = 100 pm, so the
range of atomic radii is 0.3 to 3
˚
A.
003
10.0 points
In a manyelectron atom, any two electrons
1.
have a different energy.
2.
can have either the same or a different
energy.
correct
3.
have the same energy.
Explanation:
Energy is determined by distance.
Elec
trons can have the same energy (distance from
the nucleus) but have different sets of quan
tum numbers.
004
10.0 points
Write the groundstate electron configuration
of a lead atom.
1.
[Xe] 4
f
14
5
d
10
6
s
1
6
p
3
2.
[Xe] 4
f
14
5
d
9
6
s
2
6
p
3
3.
[Xe] 4
f
14
5
d
10
6
s
2
6
p
2
correct
4.
[Xe] 4
f
14
5
d
10
6
p
4
5.
[Xe] 4
f
14
5
d
5
6
s
1
6
p
6
7
s
2
[Xe] 4
f
14
5
d
10
6
s
2
6
p
2
.
Version 725 – Exam 1 – Mccord – (50970)
2
005
10.0 points
What is the de Broglie wavelength of a bowl
ing ball rolling down a bowling alley lane?
Assume the mass of the ball is 4500 g and it
is moving at 4.12 m/s.
1.
3
.
574
×
10

38
m
2.
3
.
57389
×
10

35
m
correct
3.
1
.
4725
×
10

37
m
4.
1
.
229
×
10

32
m
Use the rules for the quantum numbers:
If
n
= 4 then
ℓ
= 0
,
1
,
2
,
3; however, for
m
ℓ
=

1,
ℓ
= 1
,
2
,
3. Each of these permit
ted sets of values of
n
,
ℓ
and
m
ℓ
specifies ONE
orbital:
n
= 4,
ℓ
= 1,
m
ℓ
=

1:
4
p
n
= 4,
ℓ
= 2,
m
ℓ
=

1:
4
d
n
= 4,
ℓ
= 3,
m
ℓ
=

1:
4
f
and each orbital can have
m
s
=
±
1
2
;
i.e.
, can
hold two electrons.
Explanation:
006
10.0 points
How
many
electrons
can
possess
this
set
of
quantum
numbers:
principal
quantum
number
n
= 4, magnetic quantum number
m
ℓ
=

1?
9.
16
10.
12