PSYC123 - Assignment Final.docx

# Q10 if you were to graph this information the

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Q.10. If you were to graph this information (the frequency of the different scores), what type of graph would you use? (0.5 mark) If I were required to graph this information, I would use a frequency histogram graph. Q.11. Below is a template of a graph. You want to graph the frequency and distribution of the UPI scores. Label the axes below appropriately. (0.5 mark) Q.12. You began your research by measuring psychopathy levels in 12 randomly selected university students, and tested them with the Universal Psychopathy Instrument (UPI). 8 2017 Final V3 PSYC123 Assignment – Student Version 1 2 3 0, 9 1, 2, 3, 5, 6, 6, 7, 7, 7, 8 1 Frequency Distribution

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From the literature you hypothesise that university students will demonstrate lower psychopathy scores compared to the general population. Previous studies indicate that the general population statistics for psychopathy scores on the UPI is µ = 24.97; σ 0.59. You set your alpha level at α = .05. You now need to conduct the calculations to test your hypothesis that your sample of university student’s levels of UPI is lower than the general population (µ = 24.97; σ 0.59). Setting your alpha level at α = .05, conduct the appropriate hypothesis testing using the 6 steps. (Total = 5.5 marks) a) Step .1.: Analyse the question and extract the information. (0.6 marks) - Hypothesis states that university students will demonstrate lower psychopathy scores compared to the general population. - Previous studies indicate the statistics for the general population for psychopathy scores on the UPI are as follows: μ = 24.97 σ = 0.59 a = 0.05 N = 12 b) Step .2.: Determine design and test type (and check assumptions). (0.8 marks) - One sample is provided and the population standard deviation is known - The sample is randomly selected from the population of interest - The test type will be a one-sample z-test - Z = ´ X μ σ ´ x = 1.158 σ ´ X = σ N = 0.170 c) Step .3.: State the hypotheses (relevant to the test type). (1.0 mark) - Null hypothesis H0: μstudents = 24.97 The population mean of UPI scores of students is equal to 24.97 - Alternate hypothesis H1: μstudents ≠ 24.97 The population mean of UPI scores of students is not equal to 24.97 d) Step .4.: Decision Rule. (0.8 marks) - If zobserved is more extreme than zcritical (+1.96), we reject the null hypothesis Zcritical = 1.96 Zobserved = 1.158 e) Step .5.: Conduct the test (calculate the statistic(s)). (1.0 mark) - Z = ´ X μ σ ´ x = 1.158 σ ´ X = σ N = 0.170 - ´ X = 25.167 9 2017 Final V3 PSYC123 Assignment – Student Version
- N = 12 - N = 3.464 - μ = 24.97 - = 0.59 - σ ´ X = 0.59 12 = 0.170 - Zobserved = 25.167 24.97 0.170 = 1.158 f) Step .6.: Make decision based on decision rule, and draw your conclusions. (0.8 marks) - If Zobserved is more extreme than + Zcritical, we reject the null hypothesis - Zobserved is 1.158 - Zcritical is +1.96 - We accept the null H0 and conclude that the UPI scores of students is greater than that of the general population.

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