What is the ground-state energy of ten nonin-teracting bosons in a one-dimensional box oflength L?1.5h24m L2correct2.h28m L23.h216m L24.7h24m L25.3h28m L26.0Explanation:The ground-state energy of a single particlein a one-dimensional box of length L isE0,1particle=h28m L2,so for ten bosons,E0,10bosons=10h28m L2=5h24m L2.

01010.0pointsRemember the energies of a particle confinedto a one-dimensional box of lengthL.Theyare given byEn= (nh)2/(8mL2),wherenisthe principal quantum number. Now supposewe place three identical fermions into this box.Ignore the fermion spin quantum number, andconsider onlyn.Each fermion can only gointo a level not already occupied by anotherfermion, since no two fermions in the sameregion of space can be in the same state. Whatwill be the minimum total energy of the threefermions in the box?

mughawish (am72963) – HW16 – coker – (56000)4

10.0pointsYou have 6 fundamental particles that areabsolutely identical.You want to containthem within a submicroscopic cubical box.You find that you can place every one of theseparticles in the same state, the ground stateof the box. What kind of particle must thesebe?