b Find the probability that both are republicans First as republican PR 30 50

B find the probability that both are republicans

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b. Find the probability that both are republicans. First as republican: P(R)= 30 50 = 0.6 Second as republican: P(R2) = 29 49 = 0.591 0.6 ×0.591=0.355 Therefore, the chance for both governors selected from Republic party is 35.5%
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c. d. Probability of two governors from the same party Both from Republic party: 0.355 Both from Democratic Party: 0.155 0.355+0.155=0.51 As a result, the chance is 51% e. Probability of two governors from different parties. First Republican+ second Democratic = 0.233 First Democratic +second Republican = 0.236 0.233+0.236=0.469 Therefore, the chance is 47% 4.186 Injured Americans. The National Center for Health Statistics compiles data on injuries and publishes the information in 4.6 The Multiplication Rule; Independence 221 Vital and Health Statistics. A contingency table for injuries in the United States, by circumstance and gender, is as follows. Frequencies are in millions. a. Find P ( C 1). ( 8 + 1.3 ) ÷ 61.4 = 0.1515 .Thus, P ( C 1 ) = 15.15% b. Find P ( C 1 | S 2). 1.3 ÷ 25.8 = 0.0504 .Thus, P ( C 1 | S 2 ) = 5.04% c. Are events C 1 and S 2 independent? Explain your answer. Event C1 is not independent of event S2 because the percentage of work injuries among female and male (15.15%) is not the same as the percentage of injuries among female at work (5.04%).
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  • Fall '16
  • MASUCK,CAROL
  • Academic degree, Doctor of Philosophy, Thomas Edison State College, National Governors association, republic party

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