# Corresponding charge on the outer cylindri cal shell

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7. | E | = λ R 3 3 π ǫ 0 r 2 8. | E | = 2 λ 3 π ǫ 0 r 9. | E | = λ 4 π ǫ 0 r correct 10. | E | = λ 2 π ǫ 0 r Explanation: Pick a cylindrical Gaussian surface with the radius r that is outside both cylinders and apply Gauss’s law:
corresponding charge on the outer cylindri- cal shell per unit length is ( - λ/ 2) (half the magnitude and opposite in sign) . λ R 1 R 2 R 3 - λ/ 2 Find the magnitude of the electric field at the point a distance r from the central axis of the inner cylinder, where r > R 3 (outside both cylinders). | E | · · 2 π r = (1 / 2) λℓ ǫ 0 | E | = λ 4 π ǫ 0 r . 004 10.0points Three point charges, each of magnitude q , are placed at 3 corners of a square with sides of length L . The charge farthest from the empty corner is negative ( - q ) and the other two charges are positive (+ q ). + + - A B L O What is the potential at point A ?
Version 081 – mid2 58010 – yeazell – (58010) 3 7. V = parenleftbigg 2 - 1 2 parenrightbigg k q 2 L 8. V = 2 2 k q L 9. V = parenleftbigg 2 - 1 2 parenrightbigg k q L correct 10. V = 2 2 k q L 2 At what distance from the conductor is
the magnitude of the resulting magnetic field 0 . 000142 T?
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