A 3 0 2 0 0 1 2 1 0 0 2 0 4 0 0 0 0 0 1 3 0 0 0 2 2

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A=3020 01210 02040 00 0 01 30 0 02 2det(A) =256
det(A) det(D)det(B) det(C).ACDB
A=1 40 3B=1 04 1C=0514D=4 13 0=-16det(A) det(D)det(B) det(C) =-14ABCD10x12x2=15x1+3x2=A unique solution exists for the linear system.A unique solution does not exist for the linearsystem.,,,63
11/21/17, 00(03UW Common Math 308 Section 5.29.1/1 points |Previous AnswersHoltLinAlg2 5.2.051a.Determine if the statement is true or false, and justify your answer.Suppose thatAis amatrix and thatBis the matrix obtained by multiplying the thirdcolumn ofAby2. Then4×det(B) =2det(A).4).
Page 4 of 410.1/1 points |Previous AnswersHoltLinAlg2 5.2.069.VerifySylvester's determinant theorem, which states thatfor anymatrixAandmatrixB.
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