The expression for the acceleration of the cart for

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The expression for the acceleration of the cart for the experiment you did in lab is where is kept constant throughout.(a) Consider the situation when friction force is zero. What is the expression for the accelerationof the cart now? (Use the following as necessary: m1, m2, and g= (m1gf)(1+ m2m1+ m.)
If you now double the hanging mass m1, (so m= 2m1), how will the value of the denominatorfor the expression for the acceleration change?
a= (m1gf)(1+ m2m1+ mm)2
What is the expression for the acceleration now? (Use the following as necessary: m1, m2, andg.)Based on your answers to the previous parts, what conclusion can you draw about theacceleration of the cart?(b) Consider the situation when friction force is non-zero. What is the expression for theacceleration of the cart now? (Use the following as necessary: m1, m2, f, and g.)If you now double the hanging mass m1, (so m= 2m1) how will the value of the denominatorfor the expression for the acceleration change?.

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