Above the device is air which has index of refraction

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Above the device is air which has index ofrefraction,n1= 1. See the figure below.#1#2(part 1 of 2) 10.0 pointsA pair of narrow, parallel slits separated by0.385 mm are illuminated by green light ofwavelength 553 nm. An interference patternis observed on a screen 1.05 m away from theplane of the slits.Calculate the distance from the centralmaximum to the first bright region on ei-ther side of the central maximum.Determine the minimum film thickness thatTherefore, the required thickness ist=λ4n2=593 nm(4) (1.3)= 114.038 nm.Typically, such reflecting coatings reduce thereflective loss from 30% (with no coating) to10% (with coating), thereby increasing thecell’s efficiency, since more light is available tocreate carriers in the cell. In reality, the coat-ing is never perfectly reflecting because therequired thickness is wavelength-dependentand the incident light covers a wide rangeof wavelengths. Glass lenses used in the cam-eras and other optical instruments are usu-ally coated with a transparent thin film, suchas magnesium fluoride (MgF2), to reduce oreliminate unwanted reflection.More impor-tant, such coatings enhance the transmissionof light through the lenses.006(part 1 of 2) 10.0 pointsA pair of narrow, parallel slits separated by0.385 mm are illuminated by green light ofwavelength 553 nm. An interference patternis observed on a screen 1.05 m away from theplane of the slits.Calculate the distance from the centralmaximum to the first bright region on ei-ther side of the central maximum.
produces the least reflection at a wavelengthof 593 nm.2
Kapoor (mk9499) – oldhomework 35 – Turner – (60230)4Calculate the distance between the first andsecond dark bands.Determine the wavelength of the light. Besure to use the small angle approximation,sin(θ)θ

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Term
Spring
Professor
Turner
Tags
Physics, Work, Light, refractive index, Kapoor

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