Chapter 20--Principles of R

# Calculate

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29. Calculate 010009000003080500000000e104000000000400000003010800050000000b02000000 00050000000c02200019000400000004010d0004000000070103000500000014020000 0000e1040000410b2000cc0020001900000000002000190000000000280000001900000 02000000001001800000000008009000000000000000000000000000000000000ffffffffff ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff ffffffffff00ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff ffffffffffffffffffffffffffffffffff00ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff ffffffffffffffffffffffffffffffffffffffffffffffffffffffffff00ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff00ffffffffffffffffffffffffffffffffffffffffffff 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00fafdfbfffffffefefe000000fffffffefefe000000fffeff000200fdfffefffffffffffffffffffefefefffefffffdfff efefefefefeffffffffffffffffffffffffffffffffffffffffff00fffffffffffffefefefdfdfd010101fffffffefefeffffff0202 02fffffffffffffffffffefefefefefefffffffefefeffffffffffffffffffffffffffffffffffffffffffffffffffffff00fefefefefefeff ffff000000010101000000000000000000000000fefefefefefe020202fefefefffffffffffffefefeff ffffffffffffffffffffffffffffffffffffffffffffffffffff00fffffffffffffefefefffffffdfdfdfffffffefefefffffffefefeffffff03 0303fefefe020202fdfdfdfffffffefefeffffffffffffffffffffffffffffffffffffffffffffffffffffff00fffffffffffffdfdfdff fffffffffffffffffffffffefefefefefefefefefdfdfd000000fffffffffffffffffffefefeffffffffffffffffffffffffffffffffffff ffffffffffffffffff00fffffffffffffffffffefefefefefefffffffefefeffffffffffffffffffffffffffffffffffffffffffffffffffffffffff ffffffffffffffffffffffffffffffffffffffffffffffffff00fefefefffffffefefefffffffefefefffffffffffffefefefffffffcfcfcffff fffffffffdfdfdfffffffefefeffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff00fffffffffffffefefefefefeffffff fffffffefefefffffffefefefffffffffffffefefefffffffffffffffffffefefeffffffffffffffffffffffffffffffffffffffffffffffffffffff 00fefefefefefefffffffffffffffffffefefefffffffffffffdfdfdfefefefffffffffffffefefefffffffefefeffffffffffffffffff ffffffffffffffffffffffffffffffffffffffffff00030000000000 for the electrochemical cell below, Pb(s) |PbCl 2 (s) | Cl
(aq, 1.0 M) || Fe 3+ (aq, 1.0 M), Fe 2+ (aq, 1.0 M) | Pt(s) given the follo wing redu ction half- react ions. Pb 2+ (aq) + 2 e ® Pb(s) E = –0.126 V PbCl 2 (s) + 2 e ® Pb(s) + 2 Cl (aq) E = –0.267 V Fe 3+ (aq) + e ® Fe 2+ (aq) E = +0.771 V Fe 2+ (aq) + e ® Fe(s) E = –0.44 V
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